Question

The sum of a two-digit number and the number obtained by reversing the digits is 121. The two digits differ by one. Find the number.

Answer 1

Answer:

Let no at ones= x

Let no. at tens=10(x+3)

=10x+ 30

New no.

Let no. at ones place x+3

let no. ta tens place 10x

10x +30+x + 10x + x +3= 121

22x=88

x=88/22

x=4

the original no. is 74

the new no. is 47