Question

The sum of a two-digit number and the number obtained by interchanging its digit is

110. If the original number exceeds six times the sum of its digits by 4. find the original​

Answer 1

Answer:

Step-by-step explanation:

(10x+y) + (10y +x) = 110............(i)

10x+y = 6(x+y) + 4.....................(ii)

(i)

10x+y+10y+x=110

11x+11y=110                                    (divide the entire equation by 11)

x+y=10

(ii)

10x+y=6x+6y+4

4x =  5y + 4

4x-5y=4

by elimination method

(x+y = 10) 5

5x+5y = 50

4x-5y = 4......(ii)                     (subtract equation (i) from (ii) )

9x = 54

x = 6

since,

x + y = 10

y = 10-6

y=4

Orignal number is 64!

Hope this helps!