The sum of a two-digit number and the number obtained by reversing its digits is 121. Find the number if it’s unit place digit is 5
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I remember the question but not the answer
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Step-by-step explanation:
Unit's place digit = 5
Let ten's place digit be x
Original number = 10x+5
Reversing the order we get = 5x+10
Adding both numbers = 121
10x+5+5x+10 = 121
15x + 15 = 121
15x = 121-15
x = 106/15
Hope this will help you
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