Question

The sum of a two digit number and the
number obtained by interchanging the digts
is 99. If the digit at tens place exceeds the
digit at units place by 3. find the number ​

Answer 1

Answer:

Let the digit in the unit's place be x and the digit in the ten's place be y . Then,

Number=10y+x

The number obtained by interchanging the digits is 10x+y

According to the given conditions,

(10y+x)+(10x+y)=99

=11x+11y=99

=x+y=9 ......1

And,x−y=±3 ......2 (given)

On solving equation 1 and 2 ,we get

x=6,y=3 or x=3,y=6

Hence the required number is either63 or 36

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Answer 2

Answer:

63 is the answer

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