The sum of a two digit number and the number obtained by reversing the digit is 99 if number obtained by reversing the digit is 9 more than the original number. Find the number.
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Step-by-step explanation:
10y+x+10x+y=99
11x+11y=99
x+y=9...... (1)
10y+x=10x+y+9
9y-9x=9
y-x=1.... (2)
adding eq.1 and eq.2
2y=10
y=5
x=4
Original No. is 54
and the number obtained by reverding the digit is 45
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