Question

The sum of a two-digit number and the number obtained by
reversing its digits is 121. Find the number if it's unit place cigit is
5.​

Answer 1

Step-by-step explanation:

Given units digit is x and tens digit is y

Hence the two digit number = 10y + x

Number obtained by reversing the digits = 10x + y

Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.

Then (10y+x)+(10x+y)=121

⇒10y+x+10x+y=121

⇒11x+11y=121

⇒x+y=11

Thus the required linear equation is x + y = 11.

Answer 2

Answer:

the original number is 10x+5

Step-by-step explanation:

if reversed then;

10×5+x=121

50+x=121

x=121-50

x=71

so, the original number is 10×71 =710