The sum of a two-digit number and the number obtained by reversing
the order of its digits is 121, and the two digits differ by 3. Find the
number.
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Answer:
Let the two digit number be 10x+y
On reversing its digits, we get the number 10y+x
Given, (10x+y)+(10y+x)=121
11x+11y=121
=> x+y=11 --- (1)
Given, x−y=3 -- (2)
Adding (1), (2), we get
2x=14 => x=7
Substituting
x=7 in the equation (2), we get 7−y=3=>y=4
Hence, the number is 74 or 47
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