The sum of a two digit number and the number obtained by reversing the order of its digit is 121.If units and ten's digit of the number are x and y respectively,then write the linear equation representing the above statement.
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Answered by
5
Number:10y+x reverse:10x+y
Acc to ques;
10y+x+10x+y=121
11x+11y=121
X+y=11(dividing 11 on both the side)
Answered by
2
Units digit - x
Tens digit - y
For first number, 10y + x
For second number, 10x + y
Now its given that,
10y + x + 10x + y = 121
11x + 11y = 121
Tens digit - y
For first number, 10y + x
For second number, 10x + y
Now its given that,
10y + x + 10x + y = 121
11x + 11y = 121
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