Question

The sum of a two-digit number and the number obtained by reversing the digits is 66. If the digits of the number differ by 2, find the number. How many such numbers are there? (Please answer if you know) ​

Answer 1

Answer:

42 and 24

Step-by-step explanation:

let the original number be 10x + y

let x > y

x - y = 2

x = y + 2

original number = 10x + y

original number = 10(y + 2) + y

original number = 10y + 20 + y

original number = 11y + 20

new number = 10y + x

new number = 10y + y + 2

new number = 11y + 2

11y + 2 + 11y + 20 = 66

22y + 22 = 66

22y = 44

y = 2

x = y + 2

x = 2 + 2

x = 4

original number = 42

there can be 2 numbers of this type

42 and 24

please please mark it as brainliest