The sum of a two- digit number and the number obtained by reversing the digit is 66. If the digits of the number differ by 2, find the number. How many such numbers are there?
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18
hlo frnd hope this hlps u
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kalpafour:
The answer can also be 42.
no it would the reversed no.
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4
Let the two numbers be 10x+y and 10y+x where x and y are positive integers.
Adding the two numbers we get
11x+11y=66.
x+y=6.....1
Also, difference of th two digits it 2 so,
x-y=2.....2
Adding eq. 1 and 2,
2x=8
x=4
Substituting x,
4-y=2
y=2
So the number can be 10x+y or 10y+x.
So the required numbers are 24 and 42.
So there are two such numbers.
Adding the two numbers we get
11x+11y=66.
x+y=6.....1
Also, difference of th two digits it 2 so,
x-y=2.....2
Adding eq. 1 and 2,
2x=8
x=4
Substituting x,
4-y=2
y=2
So the number can be 10x+y or 10y+x.
So the required numbers are 24 and 42.
So there are two such numbers.
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