Question

The sum of a two digit number and the number obtained by reversing the order of its digits is 99 .if the digits of the number differ by 3.then find the number

Answer 1

THE NUMBERS ARE 63 AND 36.

Answer 2

Heya...
Here's your answer
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Let the first no. be x + 10y
( we multiply by 10 becoz the no. Is in tens place.)
Now the second no. Be 10x + y ( reversing the digits)
Now......
x + 10y + ( 10x + y) = 99
11x + 11y = 99
11 (x+y) = 99
x + y = 9 ...... (i)
Now we also know that
x - y = 3 .... (ii)
.....
solving eq. (i)
x = 9 - y
Putting this in eq. (ii)
Then ,
9 - y -y = 3
9 - 2y = 3
2y = 6
y =3
Then..,
x - y = 3
x - 3 = 3
x = 6
The no. Is 36 or 63
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Hope it helps....
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