Question

The sum of a two-digit number and the number obtained by reversing its digits is 121.
Find the number if it’s unit place digit is 5.​

Answer 1

Answer:

65

65+56=121

Let no. be t5

reverse will be 5t

t*10 + 5 + 5*10 + t = 11t + 55 = 121 => 11t = 66 => t = 6

So no. = 65

Answer 2

Answer:

The Original number = 65

Step-by-step explanation:

Let the numbers be (10x + y) and when reversed (10y + x).

This means that y is in the ones place and x is in the tens place for our number.

Now, according to the Question,

Original Number + Reversed Number = 121

(10x + y) + (10y + x) = 121

10x + y + 10y + x = 121

11x + 11y = 121

11(x + y) = 121

x + y = 121/11

x + y = 11 ----- 1

Here, we are given that,

Ones digit = 5,

But we know that,

y is in the ones digit.

So,

y = 5

Substituting y = 5 in eq.1,

x + 5 = 11

x = 11 - 5

x = 6

Thus,

Our number is 10x + y = 10(6) + 5

= 60 + 5 = 65

Hence,

The Original number = 65

Hope it helped and believing you understood it....All the best