Question

The sum of a two-digit number and the number obtained by reversing its digits is 121.

Find the number if its unit place digit is 5.

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Answer 1

Step-by-step explanation:

HOPE this answer will help you

Answer 2

Answer:

65

Step-by-step explanation:

Let the tens place of the number be x

(10x+5)+[(10×5)+x]=121

(10x+5)+(50+x)=121

10x+5+50+x=121

10x+x+50+5=121

11x+55=121

11x=121-55

11x=66

x=66÷11

x=6

Therefore, 10x+5=(10×6)+5=60+5=65