Question

The sum of a two-digit number and the number obtained by reversing its digits is 121. Find the number if its unit place digit is 5.

Answer 1

Required Answer:-

• Given, unit place digit is 5.
• Let the tens place digit be x.

A two digit number is given by 10 a + b if a is the tens place digit and b is the unit place digit.

• Then the above no. will be 10 x + 5.
• And the number obtained by reversing it will be 10(5) + x = 50 + x.

Then,

⇒ 10x + 5 + 50 + x = 121

⇒ 11x + 55 = 121

⇒ 11x = 66

⇒ x = 6

The required number is:

• The tens place is 6 and the units place is 5. Then the number is 65$.$

Answer 2

Given :-

Sum of two-digit number and the number obtained by reversing its digits is 121. Unit place = 5

To Find :-

Number

Solution :-

Let the number be 10y + 5.

Now

When it reversed the number will become 10(5) + y

10y + 5 + 10(5) + y = 121

10y + y + 5 + 50 = 121

11y + 55 = 121

11y = 121 - 55

11y = 66

y = 66/11

y = 6