the sum of a two digit number and the number obtained by reversing it's digits is 121. find the number if it's unit place is 5
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Answered by
0
Answer:
121-5=116
i hope you understand
Answered by
1
Answer:
Given units digit is x and tens digit is y
Hence the two digit number = 10y + x
Number obtained by reversing the digits = 10x + y
Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.
Then (10y+x)+(10x+y)=121
⇒10y+x+10x+y=121
⇒11x+11y=121
⇒x+y=11
Thus the required linear equation is x + y = 11.
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