Question

the sum of a two digit number and the number obtained by reversing the digits is 110. if 10 is subtracted from the first number.,the new number is 4 more than 5 times the sum of digits in the first number,find the first number

Answer 1

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one's digit =x
ten's digit=y
the no=10y+x
sum of the digits=x+y
reversed number+10x+y
it is given that the sum of
10y+x+10x+y=110
11y+11x=110
y+x=10.................(eq 1)
10y+x-10=5(x+y)+4
10y+x-10=5x+5y+4
10y-5y+x-5x=4+10
5y-4x=14..........(eq 2)
from eq 1 and 2
using elimination method
u can find the answer