Question

The sum of a two-digit number and the number obtained by reversing its digits is 121. Find the number if it’s tens place digit is one more than the unit place digit.

Answer 1

Answer:

65

Step-by-step explanation:

Let the no be 10x + y

Then it's reverse will be 10y + x

according to question

(10x + y ) + (10y + x) = 121

11x + 11y = 121

x+ y = 11 ---(1)

Also it is given that,

tens place is one more than units place

so, x-y= 1 --(2)

by solving (1) and (2) , we get

x= 6 and y= 5

so the number is 65

This will help you