Question

the sum of a two digit number and the number obtained by reversing it's digit is 121 . Find the number if it's unit place is 5 ( only one variable)​

Answer 1

Answer:

11

Step-by-step explanation:

Given units digit is x and tens digit is y

Hence the two digit number = 10y + x

Number obtained by reversing the digits = 10x + y

Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.

Then (10y+x)+(10x+y)=121

⇒10y+x+10x+y=121

⇒11x+11y=121

⇒x+y=11

Thus the required linear equation is x + y = 11.

Hope it helps!!!

Answer 2

Answer:

65

Step-by-step explanation:

Let ten's digit be x.

Therefore number is:

10*x + 5= 10x + 5

By reversing the number:

10*5 + x= 50 + x

Sum of both numbers:

10x + 5 + 50 + x = 121

11x + 55 = 121

11x = 121 - 55

11x = 66

x = 66/11

x = 6

Number is 65