Question

The sum of a two digit number and the number obtained by reversing it's digits is 132. Find the sum of the two digits of the number.

Answer 1

Step-by-step explanation:

Given:-

The sum of a two digit number and the number obtained by reversing it's digits is 132.

To find:-

Find the sum of the two digits of the number?

Solution:-

Let the digit at tens place be X

The place value of X = 10×X = 10X

Let the digit at ones place be Y

The place value of Y = 1×Y = Y

The two digit number = 10X+Y--------(1)

The number obtained by reversing the digits then

The new number = 10Y+X-------------(2)

On adding (1)&(2) then

=> 10X+Y+10Y+X

=> (10X+X)+(Y+10Y)

=> 11X+11Y

According to the given problem

The sum of a two digit number and the number obtained by reversing it's digits = 132.

=> 11X+11Y = 132

=> 11(X+Y) = 132

=> X+Y = 132/11

=> X+Y = 12

Answer:-

The sum of the two digits of the number = 12

Answer 2

QuEstion :

The sum of a two digit number and the number obtained by reversing it's digits is 132. Find the sum of the two digits of the number.

To Find :

The sum of the two digits of the number.

GivEn Data :

Let the unit's digit be y

Let the ten's digit be x

So the original number is 10x + y

After interchanging the digits the new number is x + 10y

Sum of the number is 10x + y

The sum of the digit is x + y

So according to the question,

• (10x + y) + (x + 10y) = 132

• 10x + y + x + 10y = 132

• 11x + 11y = 132

• 11(x + y) = 132

• x + y = 132/11

• x + y = 12

Hence, the sum of the two digits of the number is 12

Regards

# BeBrainly