Math, asked by sharmasomya32232, 1 month ago

the sum of a two digit number and the number obtained by reversing the order of it's digit is 121 and the two digit differ by 3 find the number

Answers

Answered by joothappy29
3

Answer:

Let the two digit number be 10x+y

On reversing its digits, we get the number 10y+x

Given, (10x+y)+(10y+x)=121

11x+11y=121

=> x+y=11 --- (1)

Given, x−y=3 -- (2)

Adding (1), (2), we get

2x=14 => x=7

Substituting

x=7 in the equation (2), we get 7−y=3=>y=4

Hence, the number is 74 or 47

Step-by-step explanation:

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