Question

The sum of a two-digit number and the number obtained by reversing the
digits is 66. Find the number, if the digits of the number differ by 2.

Answer 1

Step-by-step explanation:

Let say Number is XY

Value = 10X + Y

Reverse of number = YX

Value = 10Y + X

Vol 77

10X + Y + 10Y + X = 66

=> 11X + 11Y = 66

=> X + Y = 6 - eq1

IX-YI = 2

Case 1

X-Y=2 - eq2

Adding eq 1 & eq 2

=> 2X=8 => X = 4 &Y=2

Case 2

X-Y = -2 eq 3

Adding Eq 1 & eq 3

=> 2X=4 => X = 2 & Y = 4

Numbers are 42 & 24