the sum of a two digit number and the number obtained by reversing the order of its digit of 99 express this statement as a lined equation in two variables
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Answer:
let the original 2 digit number be of the form ab where a is the 10th place and b is 1s place
reverse = ba
ab + ba = 99
basically
10a+b+10b+a = 99
11a + 11b = 99
a+b=9
Answered by
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Step-by-step explanation:
10a+b+10b+a=99
11a+11b= 99
a+b=9
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