Question

The sum of a two-digit number and the number obtained by reversing its digits is 121. Find the number if it’s unit place digit is 5.

Answer 1

Step-by-step explanation:

Given units digit is x and tens digit is y

Hence the two digit number = 10y + x

Number obtained by reversing the digits = 10x + y

Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.

Then (10y+x)+(10x+y)=121

⇒10y+x+10x+y=121

⇒11x+11y=121

⇒x+y=11

Thus the required linear equation is x + y = 11.

Answer 2

• 65 + 56 = 121

Let no. be t5

• reverse will be 5t

• $t \times 10+5+5 \times 10+t$

• =11t+55=121

• $\Rightarrow \: 11t=66$

• =>t=6

• So no.=65

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