The sum of a two digit number and the number obtained by reversing the order of its digits is 88 Express is information in linear equation
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Hey buddy! Here's your answer!
Let initial number be 10x + y
Number obtained by reversing the digits = 10y + x
10x + y + 10y + x = 88
11x + 11y = 88
11(x + y) = 88
x + y = 8
Hope this helps! :)
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