Math, asked by an3ner8jeeskaredsc, 1 year ago

The sum of a two digit number and the number obtained by interchanging the digits is 132. if the two digits differ by 2, find the number(s)

Answers

Answered by tejasmba
174

Let us assume the x and y are the two digits of a two-digit number

Therefore, two-digit number = 10x + y and number obtained by interchanging the digit is = 10y + x

Given:

10x + y + 10y + x = 132

11x + 11y = 132

x + y = 12

x = 12 – y ------------1

Also given that:

x – y = 2 ----------2

Substitute the value of x from eqn 1 in the eqn 2

12 – y – y = 2

2y = 10

y = 5

Therefore, x = 12 – 5 = 7

Two digit number is = 10x + y = (10 * 7) + 5 = 75 
and the number obtained by interchanging the digits is = 10y + x = 10*5 + 7 = 57.
Answered by Anonymous
56

Answer:

Step-by-step explanation:

Let us assume the x and y are the two digits of a two-digit

number

Therefore, two-digit number = 10x + y and number obtained by interchanging the digit is = 10y + x

Given:

10x + y + 10y + x = 132

11x + 11y = 132

x + y = 12

x = 12 – y ------------1

Also given that:

x – y = 2 ----------2

Substitute the value of x from eqn 1 in the eqn 2

12 – y – y = 2

2y = 10

y = 5

Therefore, x = 12 – 5 = 7

Two digit number is = 10x + y = (10 * 7) + 5 = 75 

and the number obtained by interchanging the digits is = 10y + x = 10*5 + 7 = 57

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