Math, asked by sha3vyliTanidar, 1 year ago

The sum of a two-digit number and the number obtained by reversing its digits is 88. The digit at the units place is thrice the digit at the tens place in the original number.

Answers

Answered by tejasmba
3
Let the number be 10x + y.

Then, given, y = 3x and

10x + y + 10y + x = 88

Or 11x + 11y = 88

Or x + y = 8.

Substituting the value of y = 3x in x + y = 8, we get

x + 3x = 8

or 4x = 8.

Therefore x = 8/4 = 2.

and y = 3*2 = 6.

Therefore, the number is 10*2+6 = 26.
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