The sum of a two-digit number and the number obtained by reversing its digits is 88. The digit at the units place is thrice the digit at the tens place in the original number.
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Let the number be 10x + y.
Then, given, y = 3x and
10x + y + 10y + x = 88
Or 11x + 11y = 88
Or x + y = 8.
Substituting the value of y = 3x in x + y = 8, we get
x + 3x = 8
or 4x = 8.
Therefore x = 8/4 = 2.
and y = 3*2 = 6.
Therefore, the number is 10*2+6 = 26.
Then, given, y = 3x and
10x + y + 10y + x = 88
Or 11x + 11y = 88
Or x + y = 8.
Substituting the value of y = 3x in x + y = 8, we get
x + 3x = 8
or 4x = 8.
Therefore x = 8/4 = 2.
and y = 3*2 = 6.
Therefore, the number is 10*2+6 = 26.
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