Question

The sum of a two digit number and the number obtained by interchanging it's digits is 99. find the number

Answer 1

Answer:

Step-by-step explanation:

Let we assume no.is36.

Interchanging no.is 63

63+36=99

So,the answer is 36.

Answer 2

$\huge \bigstar$$\huge\bold{\mathtt{\purple{✍︎A{\pink{N{\green{S{\blue{W{\red{E{\orange{R✍︎}}}}}}}}}}}}}$$\huge \Rightarrow$

$\bold {Solution:}$

let the digit in the units place be $\large y$ and that in the tens place $\large x$.

Then the number is $\large 10x+y$.

the number obtained by interchanging the digits is $\large 10y + x$.

the sum of these two numbers is 99.

∴ $\large 10x+y+10y+x=99$

∴$11x+11y=99$

∴$x+y=9$

If we take the values of $\large x$ as 1,2,3.......,etc.,the corresponding values of y will be 8,7,6 .... etc.

∴ The numbers are 18,27,36,etc.