The sum of a two digit number and the number obtained by reversing
its digits is 121. Find the number if its units place digit is greater than
the tens place digit by 7.
Answers
Answered by
6
...!......,,.,,.........,,,,
friend Here is Your Answer!
29
reverse 92,,
unit and 10 s place diff. of 29, 9-2 =7
29+92 =121
hope u understand
friend Here is Your Answer!
29
reverse 92,,
unit and 10 s place diff. of 29, 9-2 =7
29+92 =121
hope u understand
throwathigh:
hey explained
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Answered by
3
Answer:29 and 92
Step-by-step explanation:
explain plz
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