)") The sum of a two digit number and the number obtained by interchanging its digits
is 99. Find the number.
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Let the digit at unit's place be x and that at ten’s place be y .
Original number = 10y + x
Reversed number = 10x + y

Also,
When x - y = 3 ---------------- (2)
and x + y = 9
Adding we get 2x = 12
From (1) we get y = 3
Original number = 10y + x
= 36
When x - y = -3 ------------------ (3)
Adding (1) and (3) we get
and from (1) we get y = 6
Original number = 10y + x
= 63
Hence the number is 36 or 63.
Let the digit at unit's place be x and that at ten’s place be y .
Original number = 10y + x
Reversed number = 10x + y
Also,
When x - y = 3 ---------------- (2)
and x + y = 9
Adding we get 2x = 12
From (1) we get y = 3
Original number = 10y + x
= 36
When x - y = -3 ------------------ (3)
Adding (1) and (3) we get
and from (1) we get y = 6
Original number = 10y + x
= 63
Hence the number is 36 or 63.
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