The sum of a two digit number and the number obtained by interchanging the digit is 33. Then the sum of the digits is
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let x be at tens place and y be at unit place
therefore, two digit number=10x+y
number obtain by interchanging the digit=10y+x
according to condition
10x+y+10y+x=33
11x+11y=33
dividing by 11 on both sides
therefore,x+y=3
ans:- sum of digits is 3
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Answer
Original Number = 10x + y
Reversed number = 10y + x
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