Question

the sum of a two digit number and the number obtained on reversing the digits is 132.if the digits differ by 2,fins the numbers

Answer 1

★ Hi , there!!★


here is your answer !!!


let the unit digit be x


and tens digit be y


number formed => 10 x + y


now , digits get reversed => 10y + x


according to question



on adding both


we get

10 x + y + 10y + x = 132



=> 11x + 11y = 132


11 (x + y ) = 132


x + y = 12-------------------------(1)



now , digits are differ by 2


condtion => x - y = 2


or y - x = 2


as taking condition 1

from equation 1 => x + y = 12



x - y = 2
x + y = 12
========
2x = 14


x = 7

y = 5



now ,


y - x = 2
x + y = 12
========

2y = 14


y = 7


x = 5





hence , the number is 10x + y => 10 × 5 + 7


=> 57



or ,


10x + y

=> 10 × 7 + 5


=> 75



hence , your answer is => 75 or 57


hope it helps you dear friend !!!


thanks !!

Answer 2

Hey mate★★★★★★★
there is ur answer
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★★★
according to ur question
let the first (unit) digit=x
and the second digit (ten digit)= y
so ,10x+y is formed
now, the digits get reverse d
10x+y→10y+x
according to question , we get
10x+y+10y+x=132
=》11x+11y=132
=》x+y=12
x+y=12............. (1)
now x-y=2
ory-x=2(digits are differ by 2)
from equation (1)
.....
x+y=12
x-y=2
_____
2x=14
x=7
and y=5
now, y-x=2
x+y=12
______
2y=14
y=7
and x=5
Hence the no. Is
10x+y
10.5+7
=57
or 10y+x=10.7+5=75
....it is ur answer
........ I think it will help you then you mark me brainlist please please please. ....★★★★★
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★★★THE END★★★