the sum of a two digit number and the obtained by reversing its order is 66. If the digit of number differ by 2. Find the number
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Let the number be xy
(10x+y) + (10y+x) = 66
11x + 11y = 66
x+y = 6
x-y=2
2x = 8 (Adding both equations)
x=4
x+y = 6
y= 6-4 =2
hence the number is 42
(10x+y) + (10y+x) = 66
11x + 11y = 66
x+y = 6
x-y=2
2x = 8 (Adding both equations)
x=4
x+y = 6
y= 6-4 =2
hence the number is 42
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