the sum of a two digit number is 10. if 18 be subtracted from the original number,the digit interchanged place.find the number.
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sami36:
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let x, y be the digits
given x+y=10
according to the question
10x+y-18=10y+x
so, 9x-18=9y
9x-9y=18
ie, x-y=2
solving, x+y=10
x-y=2
we get, x=6 and
y=4
so, the number is 64
given x+y=10
according to the question
10x+y-18=10y+x
so, 9x-18=9y
9x-9y=18
ie, x-y=2
solving, x+y=10
x-y=2
we get, x=6 and
y=4
so, the number is 64
thank u mam
my pleasure
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