Question

the sum of a two digit number is 10 the ones digit is 9 times more than the tens digit find the number​

Answer 1

Finding number:

Step-by-step explanation:

$\ Given \value:\\\\\ sum \ of \ two \ digit = 10\\\\\ and \ ones \ digit \ is \ 9 \ times \ more \ than\ the\ tens\ digit\\\\\ Find:\\\\digit = ?\\\\\ Solution:\\\\\ let \ digit =\ ab\\\\\ where \ a \ is \ tens \ place \ and \ b \ is\ once \ place\\\\ \ according \ to \ condition \\\\a+b=10 ...............(i)\\\\b=9a....(ii)\\\\\ put \ the\ value \ of \ b \ in \ equation:\\\\ a+9a= 10\\\\10a=10\\\\a=\frac{10}{10}\\\\a= 1\\\\\ put \ the \ value\ of \ a \ in \ equation (ii)\\\\b=9$

$\ So, \ the\ digit \ is \ 19$

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