Question

The sum of a two digit number is 11 if the number obtained by reversing the digit is 9 less than the original number find the number

Answer 1

x+y=11
ATQ
10x+y-(10y+x)=9
10x+y-10y-x=9
9x-9y=9
x-y=1
x+y=11
2x=12
x=6
y=5
the original number is 10x+y=65

Answer 2

Hey friend here's your answer
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Let the unit digit = x
ten's digit = y

x + y = 11 --------1

According to question ,

10y + x = 10x + y -9

10y - y = 10x - x - 9
9x - 9 = 9y
9x - 9y = 9
x - y = 1 --------2

By solving equation 1 and 2

We get,
x = 6
y = 5

We know , unit digit = x
and tens = y

So that the number is 65

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#Hope its help you a lot my dear#
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