Question

the sum of a two digit number is 12 . the number is 6 time the unit digit find the number​

Answer 1

Answer:

Let assume number at tens place = x

And number at units place = y

So number = 10x + y

Given that sum of two digits is 12

=> x + y = 12  

=> y = 12 – x        ------ (1)

Also given number is 6 times the unit digit

=> 10x + y = 6y

=> 10x – 5y = 0

=> 2x – y = 0      ------- (2)

Substituting value of x from equation (1) in equation (2) we get

=>2x –( 12 – x) = 0

=> 3x = 12  

=>x = 4

From (2) y = 12 – x = 12 - 4 = 8

Hence required number is 10 x 4 + 8 = 48.

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Answer 2

Step-by-step explanation:

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Answer:

48

Step-by-step explanation:

Let the digits be x and y. Given x+y=12

The two digit number will be 10*x+y.

$\sf\ \: 10*x+y=6*y$

$\sf\ 10x=5y$

2x=y in x+y=12 gives x+2x=3x=12 which gives x=4

x=4 implies y=8 and the number is 10*4+8=48