the sum of a two digit number is 16. if digit at tens place is increased by 8 and digit at units place is decreased by 8 the digits of number found to be reversed. find the original number.
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Answer:Let the no. is ab (a at tens place and b at ones place)
according to first condition the sum is 16 Implies a+b=16.
According to second condition if a and b interchanged
the difference become 18
i.e. ba-ab = 18 this implies
(10b + a) -(10a +b) = 18
10b-b +a -10a =18
b -a =2 this gives b=9 and a=7
The No. is 79
Step-by-step explanation:
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