the sum of a two digit number is 5.if the digits are reversed, the number is reduced by 27.Find the number by elimination method in linear equation
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let X and Y be 2 nos.
original no be 10X + Y
new reversed no be X + 10Y
We know from question that ,
X + 10Y +27 = 10X + Y
therefore,
9X - 9Y = 27
X - Y = 3. -------- 1
and
X + Y = 5. -------- 2
Solving 1 and 2
X + Y = 5
X - Y = 3
2X = 8
X = 4
Sub value of X in 1
we get ,
4 + Y = 5
Y = 1
Therefore
X = 4
Y = 1
original no be 10X + Y
new reversed no be X + 10Y
We know from question that ,
X + 10Y +27 = 10X + Y
therefore,
9X - 9Y = 27
X - Y = 3. -------- 1
and
X + Y = 5. -------- 2
Solving 1 and 2
X + Y = 5
X - Y = 3
2X = 8
X = 4
Sub value of X in 1
we get ,
4 + Y = 5
Y = 1
Therefore
X = 4
Y = 1
maths5813:
Thanks again for the answer.
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