the sum of a two digit number is 7, after interchanging the digits new no. formed is 25 less than double of the original number, then find original number
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Step-by-step explanation:
Let the tens digit be x
Let the ones digit be y
Now,
Sum of the digits=7
or, x+y=7
or, x =7-y
Here,
The original no. is 10x+y
After interchanging,
10y+x
A.T.Q
10y+x=2(10x+y)-25
=> 10y+x=20x+2y
=> 8y = 19x-25
=> y = (19x-25)/8
=> y = {19(7-y)-25}/8
After this substitute the value of y in first equation
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