the sum of a two digit number is 7 if the digits are reversed the number formed is 27 less than the original number find the original number
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Let m be the ten’s digit and n be the one’s digit.
Then the number is 10m+n
Given the sum of digits is 7
So m+n=7——(1)
The reversed number is 10n+m
But it is given that the reverses number is 27 less than the original number
So 10m+n-27=10n+m
9m-9n=27
m-n=3————-(2)
(1)+(2)—->
2m=10 or m=5
So from (2), n=m-3=2
So the original number is 52
Then the number is 10m+n
Given the sum of digits is 7
So m+n=7——(1)
The reversed number is 10n+m
But it is given that the reverses number is 27 less than the original number
So 10m+n-27=10n+m
9m-9n=27
m-n=3————-(2)
(1)+(2)—->
2m=10 or m=5
So from (2), n=m-3=2
So the original number is 52
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