The sum of a two digit number is 7. When the digits are reversed and the number is decreased by three, it becomes 4 times the original number. Find the original number.
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Step-by-step explanation:
Let the one's digit number = x
Sum = 7
Tens digit number = 7 - x
So, the number becomes = 10(7 - x)+x = 70 - 9x
Reversed Number = 10x + 7
A/q,
Now, If the number is revered, then the number is decreased by 3
Revered Number = 10x + (7 - x) = 10x + 7 - x = 9x + 7
Reverse Number - 3 = 4(Original number)
9x + 7 - 3 = 4(70 - 9x)
9x + 4 = 280 - 36x
9x + 36x = 280 - 4
45x = 286
x = 286/45
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