Question

The sum of a two digit number is 9 if 27 is subtracted from number the digits interchange their places? find the number. URGENT!

Answer 1

let the digit of ones place be x
and tens place be 9-x
number=10(9-x)+X
=90-9X
INTERCHANGING
ONES PLACE=9-X
TENES PLACE=x
reversed no.=10x+9-x
=9x+9
A/Q
(90-9X)-27=9X+9
90-9-27=9x+9x
54=18x
54/18=x
3=x
ones place digit=3
tens place digit=9-x=9-3=6
number=63

Answer 2

Answer:

hope it helps you

Step-by-step explanation:

let the number in the unit place be X

then the number in the the tens place equals to

9 - X

then the number= 10 (9-x) + X = 90+9x

after interchanging the number we get =

(10 X )+ 9 - x = 9 X + 9

now, our equation is

(90 + 9 X)-27=9 X + 9

now solve this equation you will get the value of X

now applied that value of x in unit place and intense plays which is 9 - x