Question

the sum of a two-digit number obtained by reversing its digits is 121.find the number if its unit place digit is 5?

Answer 1

Answer:

HEY MATE THIS IS THE ANSWER

Step-by-step explanation:

Given units digit is x and tens digit is y

Hence the two digit number = 10y + x

Number obtained by reversing the digits = 10x + y

Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.

Then (10y+x)+(10x+y)=121

⇒10y+x+10x+y=121

⇒11x+11y=121

⇒x+y=11

Thus the required linear equation is x + y = 11.

x given (unit place) = 5

putting 5 in equation:- 5 + y = 11

Hence y = 6

x = 5 y = 6

Required number is = 56

HOPEE YOU EXCELL IN EXAMS

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Answer 2

Answer:

Step-by-step explanation:

Given units digit is x and tens digit is y

Hence the two digit number = 10y + x

Number obtained by reversing the digits = 10x + y

Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.

Then (10y+x)+(10x+y)=121

⇒10y+x+10x+y=121

⇒11x+11y=121

⇒x+y=11

Thus the required linear equation is x + y = 11.

x given (unit place) = 5

putting 5 in equation:- 5 + y = 11

Hence y = 6

x = 5 y = 6

Required number is = 56