Question

The sum of a two digit number obtained by reversing the order of the digits is 99. If the digits of the number differ by 3, find the number.

Answer 1

Answer:

let, the digits are x and y

x-y=3-------(1)

again

(10x+y)+(10y+x)=99

=>10x+y+10y+x=99

=>11x+11y=99

=>x+y=9------(2)

(1)+(2)===>

2x=12

=>x=6

putting the value of x into eqn (2)

6+y=9

=>y=3

so the digits are 6 and 3

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