The sum of a two digit number obtained on reversing the digit is 99 if the number obtained or reversing the digit is 9 more than the original number find the number
Answers
Answered by
15
Let the original number be x.
And let the number after reversing the digits is y.
It is given that y=x+9
x+y=99
x+x+9=99
x+x=99-9
x+x=90
2x=90
x=45
Thats why the original no is 45.
and reversed number is 54.
And let the number after reversing the digits is y.
It is given that y=x+9
x+y=99
x+x+9=99
x+x=99-9
x+x=90
2x=90
x=45
Thats why the original no is 45.
and reversed number is 54.
Answered by
0
Answer:
Step-by-step explanation:
Here is the answer,
Let the original number be 'x'
Let the reversed number be 'y'
The sum of both the digits on reversing is 99,
Therefore,
x+y=99 ------(1)
Its given that, the reversed number (y) is 9 more than the original number (x),
Therefore,
y=9+x -----(2)
By solving these two equations by elimination method or any other method,
y=54
Therefore,
The reversed number is 54 and the original number is 45.
Hope it helps you!!
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