Question

The sum of a two digit numbers is 12.If the new number formed by reversing the digits is greater than the original number by 18, find the number...... ................... ....plz solve with full steps .........​

Answer 1

Answer:

57

Explanation:

let it be x,y

x+y=12

   y=12-x

10y+x=10x+y +18

10y-y+x-10x=18

9y-9x=18

y-x=2

12-x-x=2

12-2x=2

12-2=2x

10/2=x

x=5

y=12-5

y=7

Answer 2

Given :-

• The sum of digits of a two digit number is 12.

• The new number formed by reversing the digits is greater than the original number by 18.

To Find :-

• What's the original number?

Solution :-

Let units place digit be x and the ten's place digit will be y.

Therefore, the number will be = 10x + y

As per question :-

Given that,

The sum of digits of a two digit number is 12.

Hence,

x + y = 12

x = 12 - y ..........eq(1)

Again, it’s given that

The new number formed by reversing the digits is greater than the original number by 18.

Therefore, the reversed number will be 10y + x.

According to the question :-

10y + x = 10x + y + 18

⟶ 9y - 9x = 18

⟶ y - x = 2......... eq(2)

Now, put x = 12 - y in eq(2)

y - x = 2

⟶ y - 12 - y = 2

⟶ 2y = 14

⟶ y = 14/2

⟶ y = 7

For getting the value of x, put y = 7 in eq(1)

⟶ x = 12 - y

⟶ x = 12 - 7

$⟶ x = 5$

Therefore, the number will be

= 10x + y

= 10 × 5 + 7

= 57

Hence, the original number is = 57