Question

The sum of a two digits number and the number obtained by reversing the digit is 66 . If the digits of the no. differ by 2. Find the number . How many such numbers are there?​

Answer 1

Answer:

i hope this will help you

Answer 2

Answer:

Answer:Number is 42.

Solution:

Let the two digits number is xy,this can be represented as 10x+y

on reversing the number the number become yx, now this can be represented as 10y+x

according to the question the sum of two digit number and the number reversing the digits is equal to 66

the digit of the number differ by 2,hence it can be represented algebraically

Now solve these two equations,here I am using Elimination method,add both equations

Hence number is 42.

it's reverse number is 24.

Verification:

42+24=66

Hope this will help you