Question

The sum of a two digits number and the number obtained by reversing the order of its digits is 121, and the digits differ by 3. find the numbers.​

Answer 1

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Let no at ones= x

Let no. at tens=10(x+3)

=10x+ 30

New no.

Let no. at ones place x+3

let no. ta tens place 10x

10x +30+x + 10x + x +3= 121

22x=88

x=88/22

x=4

the original no. is 74

the new no. is 47

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Answer 2

Answer:

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