Math, asked by arpanaial06, 4 months ago

the sum of afe of a father and his son is 60 years. if year before age of father is 4 times to his son then their prest age are​

Answers

Answered by aritikatlavaarij
4

Answer:

20 years

Step-by-step explanation:

Let the present age of son be x.

Then, present age of father is (60−x).

According to the question,

⇒ (60−x)−6=5(x−6)

⇒ 54−x=5x−30

⇒ 54+30=5x+x

⇒ 84=6x

⇒ x=

6

84

⇒ x=14

∴ Son's age after 6 years =(x+6)years

=(14+6)years

=20years.

Answered by leenamariyamvarghese
1

Answer:

Solution(By Examveda Team)

Let the present ages of son and father be x and (60 -x) years respectively. ∴ Son's age after 6 years = (x + 6) = 20 years.

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