the sum of afe of a father and his son is 60 years. if year before age of father is 4 times to his son then their prest age are
Answers
Answered by
4
Answer:
20 years
Step-by-step explanation:
Let the present age of son be x.
Then, present age of father is (60−x).
According to the question,
⇒ (60−x)−6=5(x−6)
⇒ 54−x=5x−30
⇒ 54+30=5x+x
⇒ 84=6x
⇒ x=
6
84
⇒ x=14
∴ Son's age after 6 years =(x+6)years
=(14+6)years
=20years.
Answered by
1
Answer:
Solution(By Examveda Team)
Let the present ages of son and father be x and (60 -x) years respectively. ∴ Son's age after 6 years = (x + 6) = 20 years.
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