Question

The sum of age of father and his son is 60 years After 14 years father's age will be three times the age of the son .Fins their present ages​

Answer 1

GIVEN:

Sum of ages of father and his son is 60years.

After 14 years father's age will be 3 times the age of the son.

TO FIND:

Present ages of father and his son.

SOLUTION:

Let the age of father be 'x' and his son's age be 60 - x

Sum of their ages = 69 years.

After 14 years,

Father's age = x + 14

Son's age = 60 - x + 14 = 74 - x

father's age will be 3 times the age of the son.

x + 14 = 3(74 - x)

x + 14 = 222 - 3x

x + 3x = 222 - 14

==> 4x = 208

==> x = 208/4

==> x = 52

Father's age = x = 52 years

Son's age = 60 - x = 60 - 52 = 8 years.

Therefore, their ages are 52years and 8 years.

Answer 2

Answer:

Father is 52 years and Son is 8 years old.

Step-by-step explanation:

Given :

Sum is ages = 60 years

Father will be = thrice the age of his son after 14 years

To find :

Their present ages

Solution :

Let the present ages be -

• Father as y
• Son as (60 - y)

Ages after 14 years -

• Father = (y + 14)
• Son = (60 - y) + 14

According to the question,

After 14 years father's age will be three times the age of the son

⇒ y + 14 = 3(60 - y + 14)

⇒ y + 14 = 3(74 - y)

⇒ y + 14 = 222 - 3y

⇒ y + 3y = 222 - 14

⇒ 4y = 208

⇒ y = 208/4

⇒ y = 52

Father's age = 52 years

$\rule{300}{1.5}$

★ Son's age -

⇒ 60 - 52

⇒ 8

Son's age is 8 years

Therefore, Father is 52 years and Son is 8 years old.